What sort of beast is ( / 8) in Haskell? It looks like it is a function that divides a number by 8.

*Main> ( / 8 ) 4
0.5

*Main> let a = ( / 8 )
*Main> a 4
0.5

-- Yup that works.

Does ( / 8 )  turn into a function that takes an argument, so that the "left" input to the /, becomes a right input to the function? 
What  precedence rule  is being followed here?

Thanks,

Marc