What sort of beast is ( / 8) in Haskell? It looks like it is a function that divides a number by 8.
*Main> ( / 8 ) 4
0.5
*Main> let a = ( / 8 )
*Main> a 4
0.5
-- Yup that works.
Does ( / 8 ) turn into a function that takes an argument, so that the "left" input to the /, becomes a right input to the function?
What precedence rule is being followed here?
Thanks,
Marc