On 11 November 2010 17:03, C K Kashyap <ckkashyap@gmail.com> wrote:

v1 = 1
v2 = 2

f x = case x of
v1 -> "One"
v2 -> "Two"

The closest I can thin is the following:

f x | x == v1 = "One"

| x == v2 = "Two"

But, keep in mind, this is *not* the same thing. It requires Eq on x, and you lose all the exhaustiveness/overlapping checks pattern matching provides.

HTH,

--
Ozgur Akgun