Then think of another approach to doing the problem. :)


On Mon, Jul 9, 2012 at 1:30 PM, Carlos J. G. Duarte <carlos.j.g.duarte@gmail.com> wrote:

Thanks, that's it. I had just to move the underK call inside the if:
underK k (x:xs) = if x < k then x : underK k xs else []
... I'm finding this to be a little too awkward to me!



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Regards,
KC