There are two ways to fix this. Let me see if I can get my syntax right this time :)

1.) Let GHC work out the Eq instance:
  data Shape = Square | Triangle | Circle deriving Eq

2.) Tell GHC how to do it explicitly:
  data Shape = Square | Triangle | Circle
  instance Eq Shape where
    Square == Square = True
    Triangle == Triangle = True
    Circle == Circle = True
    _ == _ = False

Note that the last line here means that any other comparisons are false.

On Mon, Dec 22, 2008 at 9:35 AM, Raeck Zhao <raeck@msn.com> wrote:
Thank you very much for your reply! It is really helpful!

But I just found another 'problem', I just realize that the list does not support the user-defined data type?
the list is also depending on the Eq function?

For example,

data Shape = Square | Triangle | Circle

when I type either

[Square, Triangle, Circle]

or

Square == Square

there are errors!

So there is no way to construct a truly polymorphic List? any way to extend the list to support some user-defined data type?

Or...  I define the Shape in a wrong way actually?

Thanks

Raeck


Date: Mon, 22 Dec 2008 09:02:53 -0500
From: wagner.andrew@gmail.com
To: raeck@msn.com
Subject: Re: [Haskell-cafe] Defining a containing function on polymorphic list
CC: haskell-cafe@haskell.org; beginners@haskell.org


The problem here is even slightly deeper than you might realize. For example, what if you have a list of functions. How do you compare two functions to each other to see if they're equal? There is no good way really to do it! So, not only is == not completely polymorphic, but it CAN'T be.

There is a nice solution for this, however, and it's very simple:

contain :: Eq a -> [a] -> Bool
contain x [] = False
contain x (y:ys) = if x == y then True else contain x ys

The "Eq a" in the type signature says that 'a' must be a member of the 'Eq' typeclass. That says, in turn, that 'a' must have == defined for it. Fortunately, most types have, or can easily derive that definition. Here is the definition of the typeclass:

class Eq a where
(==) :: a -> a -> Bool
(/=) :: a -> a -> Bool

That is, for 'a' to be a member of 'Eq', it must have a == operator which can take 2 values of that type and return a Boolean, saying whether or not they're equal, and it must also have a definition for the /= operator, which is "not equal". These two are also defined in terms of each other, so if you define ==, you get /= for free, and vice versa.

That's probably more information than you needed to know, but I hope it helps.

2008/12/22 Raeck Zhao <raeck@msn.com>
I am trying to define a containing function to see if a value is one of the elements within a list which is polymorphic, but failed with the following codes:
> contain :: a -> [a] -> Bool
> contain x [] = False
> contain x (y:ys) = if x == y then True else contain x ys it seems that the problem is the 'operator' == does not support a polymorphic check?
Any way can solve the problem? or any alternative solution to achieve the purpose?
Thanks!
Raeck

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