On 21/02/2017 15:08, Benjamin Edwards wrote:
> The thing that you might also be missing is that function application
> binds tightest. Hopefully the parenthesis that Rahul has added help you
> out there. If not:
>
> \w -> f (h w) w
>
> f will be applied to the result of (h r) which yields another function,
> which is then applied to r

Did you mean to write (h w)?

- Olumide

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