I'm looking at
this and wondering how the "as pattern" actually is working
compress (x:ys@(y:_))
| x == y = compress ys
| otherwise = x : compress ys
compress ys = ys
I'm sure it's just some version of my stab at eliminating consecutive duplicates in a list
compress :: Eq a => [a] -> [a]
compress [] = []
compress [x] = [x]
compress (x:y:xs) = if x == y then compress (y:xs) else x : compress (y:xs)
only smarter. Could someone walk me through the (x:ys@(y:_)) part?