Hi,

I am unable to compile the below code.

import Network.Socket hiding(recv)

import Network.Socket.ByteString as S (recv)

import qualified Data.ByteString.Lazy.Char8 as Char8

getMessage :: Socket -> IO String

getMessage sock = Char8.unpack <$> S.recv sock 8888

It gives the below error.

Couldn't match type ‘Data.ByteString.Internal.ByteString’

with ‘ByteString’

NB: ‘ByteString’ is defined in ‘Data.ByteString.Lazy.Internal’

‘Data.ByteString.Internal.ByteString’

is defined in ‘Data.ByteString.Internal’

Expected type: IO ByteString

Actual type: IO Data.ByteString.Internal.ByteString

In the second argument of ‘(<$>)’, namely ‘recv sock 8888’

In the expression: unpack <$> recv sock 8888

In an equation for ‘getMsg’:

getMsg sock = unpack <$> recv sock 8888

Can somebody tell me how I can return the IO String using Network.Socket.ByteString.recv?

Best Regards,

Dinesh.