You might start with looking into span.
span :: (a -> Bool) -> [a] -> ([a], [a])
For example try these,
I found some exam papers linked from this page:
http://www.cs.chalmers.se/Cs/Grundutb/Kurser/d1pt/d1pta/external.html
And I have been trying some questions from them.
I'm currently baffled by question 2(b) on this one:
http://www.cs.chalmers.se/Cs/Grundutb/Kurser/d1pt/d1pta/tenta2000-04.ps
A word is a sequence of alphabetic characters, which you can recognise
using the standard function
isAlpha :: Char -> Bool
Using span, define a function words :: String -> [String] which
finds a list of the words occurring in a string. For example,
words "Now is the winter of our discontent!"
== ["Now","is","the","winter","of","our","discontent"]
words "2+3" == []
words "1 by 1" == ["by"]
Can anyone give me a clue how to start?
--
========================
Roger Whittaker
roger@disruptive.org.uk
http://disruptive.org.uk
========================
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