On 5 June 2011 16:40, Daniel Fischer <daniel.is.fischer@googlemail.com> wrote:
\a b c d e f g h -> foo (bar a b) (baz c d e) f (quux g h)

Just for the fun of it:

$ pointfree "\a b c d e f g h -> foo (bar a b) (baz c d e) f (quux g h)"
flip flip quux . ((flip . ((flip . ((flip . ((flip . (((.) . (.)) .)) .)) .)) .)) .) . flip flip baz . (((.) . (.) . (.) . foo) .) . bar

using: http://hackage.haskell.org/package/pointfree

Cheers,
Ozgur