What sort of beast is ( / 8) in Haskell? It looks like it is a function that divides a number by 8.*Main> ( / 8 ) 40.5*Main> let a = ( / 8 )
*Main> a 40.5-- Yup that works.Does ( / 8 ) turn into a function that takes an argument, so that the "left" input to the /, becomes a right input to the function?
What precedence rule is being followed here?Thanks,Marc
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