then it works fine.This almost works, but when you actually run it you'll get an infinite loop. The reason is because pNumber if it doesn't find a match it will never actually fail, therefore many1 will continue using it forever attempting to find a match that will never occur. The reason why it never fails is that it is composed of combinators that never fail, pSkipSpaces and itself are both composed entirely of takeWhiles, which if they don't find a match they just continue on without doing anything. If you make a small change though:You have a couple problems here.In other words it matches 111 END 222 END 333 END. Try this:
P.many1 $ pNumber <* (string "END") ... which is the same as ... P.many1 (pNumber <* string "END")
ns <- (P.many1 pNumber) <* string "END"
term <- P.takeWhile1 (\c -> c >= 0x31 && c <= 0x39)
On Sat, Jun 21, 2014 at 8:47 AM, Roland Senn <rsx@bluewin.ch> wrote:
I'm trying to do a first very simple example with attoparsec.
The file "test.txt" contains the line:
START 111 2222 333 END
The following code works and gives the result: Done "\n" ["111","2222","333"]
{-# LANGUAGE OverloadedStrings #-}
import qualified Data.ByteString as BS
import Control.Applicative
import Data.Attoparsec.ByteString as P
main :: IO()
main = do
bs <- BS.readFile "test.txt"
parseTest pTest bs
pTest :: Parser [BS.ByteString]
pTest = do
string "START"
n1 <- pNumber
n2 <- pNumber
n3 <- pNumber
string "END"
return [n1, n2, n3]
pNumber :: Parser BS.ByteString
pNumber = do
pSkipSpaces
term <- P.takeWhile (\c -> c >= 0x31 && c <= 0x39)
pSkipSpaces
return term
pSkipSpaces :: Parser ()
pSkipSpaces = do
P.takeWhile (\c -> c == 0x20)
return ()
Unfortunately I must have exactly three numbers between START and END. To make this more flexible, I changed pTest:
pTest :: Parser [BS.ByteString]
pTest = do
string "START"
ns <- P.many1 $ pNumber <* (string "END")
return ns
Now the program fails with: Fail "2222 333 END\n" [] "Failed reading: takeWith"
Why ??
Many thanks for your help!
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