> The indentation on the second line would generate a parse error, the same as it does now.
What parser error is that? Both

function 0 = 0 where
 fun     1 = 1
function 2 = 2

and

function 0 = 0 where
 fun     1 = 1
 fun     2 = 2

works for me.

/J

On 23 August 2010 11:46, John Smith <voldermort@hotmail.com> wrote:
The indentation on the second line would generate a parse error, the same as it does now.


On 23/08/2010 12:32, Jonas Almström Duregård wrote:
Maybe because of this:

function 0 = 0 where
 fun     1 = 1
         2 = 2

The last declaration (2=2) can define either fun or function. I'm not saying this is a major problem, but there may be
other problems like these.

/J

On 23 August 2010 11:15, Brent Yorgey <byorgey@seas.upenn.edu <mailto:byorgey@seas.upenn.edu>> wrote:
 > On Mon, Aug 23, 2010 at 09:33:13AM +0300, John Smith wrote:
 >> Why doesn't Haskell allow something like this?
 >>
 >> fac 0 = 0
 >>     1 = 1
 >>     x = x * fac (x-1)
 >>
 >> This would be clearer than repeating the function name each time,
 >> and follow the same pattern as guards and case.
 >
 > Good question.  I don't know of any particular reason.
 >
 > -Brent

_______________________________________________
Beginners mailing list
Beginners@haskell.org
http://www.haskell.org/mailman/listinfo/beginners