Of course not. What a silly thing to suggest. I'm saying that parsing is not relevant to the behavior of ($). The parser can't tell the *semantic* difference between $ and any other operator.On Mon, Jun 8, 2015 at 11:02 AM Mike Meyer <mwm@mired.org> wrote:Are you saying that GHC doesn't have a haskell parser?On Mon, Jun 8, 2015 at 12:06 PM, Rein Henrichs <rein.henrichs@gmail.com> wrote:The point is that there is no parsing happening here. Just evaluation.