On 4 May 2013 19:33, Costello, Roger L. <costello@mitre.org> wrote:

<snip>

But then I saw this in an article:

        ($ 3) odd

What does ($ 3) mean? I thought the first argument to ($) is a function?

I checked the type of ($ 3) and it is:

        ($ 3) :: Num a => (a -> b) -> b

I don't understand that. How did that happen? Why can I take a second argument and wrap it in parentheses with ($) and then that second argument pops out and becomes the argument to a function?

These are called operator sections. Take a look at http://www.haskell.org/haskellwiki/Section_of_an_infix_operator
 

I decided to see if other functions behaved similarly. Here is the type signature for the "map" function:

        map :: (a -> b) -> [a] -> [b]

That looks very similar to the type signature for ($). So, I reasoned, I should be able to do the same kind of thing:

        let list=[1,2,3]
        (map list) odd

But that fails. Why? Why does that fail whereas a very similar looking form succeeds when ($) is used?

Because (map list) is an ordinary function application since operator sections apply only to infix operators. On the other hand, had you written (`map` list), it would have worked as you expected.

λ. let list = [1, 2, 3]
λ. (`map` list) odd
[True,False,True]

--
Denis Kasak