Thank you all!! 

Got it working with Data.List.transpose

On Mon, May 18, 2015 at 5:09 PM, Henk-Jan van Tuyl <hjgtuyl@chello.nl> wrote:
On Mon, 18 May 2015 13:23:41 +0200, Dananji Liyanage <dan9131@gmail.com> wrote:

Hi All,

I'm building a 9x9 grid like list, and I want to extract each column of
that grid.

My input is a list of integers as follows;

input = [0, 0, 0, 0, 0, 0, 4, 0, 9,
0, 0, 0, 0, 8, 0, 0, 5, 0,
7, 0, 2, 4, 5, 3, 6, 0, 0,
6, 7, 0, 0, 0, 1, 5, 0, 2,
2, 0, 8, 7, 0, 4, 3, 0, 1,
9, 0, 4, 5, 0, 0, 0, 8, 6,
0, 0, 6, 3, 1, 9, 8, 0, 7,
0, 2, 0, 0, 7, 0, 0, 0, 0,
1, 0, 7, 0, 0, 0, 0, 0, 0]

Try the function chunksOf of package split[0]

Regards,
Henk-Jan van Tuyl


[0] http://haddocks.fpcomplete.com/fp/7.8/20140916-162/split/Data-List-Split-Internals.html#v:chunksOf


--
Folding@home
What if you could share your unused computer power to help find a cure? In just 5 minutes you can join the world's biggest networked computer and get us closer sooner. Watch the video.
http://folding.stanford.edu/


http://Van.Tuyl.eu/
http://members.chello.nl/hjgtuyl/tourdemonad.html
Haskell programming
--



--
Regards,
Dananji Liyanage