No, not really

the '.' operator is function composition, so f.g is a new function with f applied over g.

h=f.g ==> h x = f ( g x )

the '$' is the apply operator, and it applies the right side to the left side:

h = f $ x ==> h= f ( x )

You can check this looking at their types

(.) :: (b -> c) -> (a -> b) -> a -> c
($) :: (a -> b) -> a -> b

the first one takes two functions and return a new function. The second takes a function and a value and returns a value.

Regards

Rafael

On Sun, Oct 30, 2011 at 15:39, <haxl@nym.hush.com> wrote:

Doesn't . and $ do the same thing? 狢 always get confused about
that, like when would I use one over the other.

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Rafael Gustavo da Cunha Pereira Pinto