Yes, thank you Simon, my test works if I wait at least 1 second before the two loads, so I'd say I run exactly into that issue. So I can adapt my code to only remove the target if the files do not give me a time difference.

Thanks a million!

JP


On Fri, Jan 25, 2013 at 5:29 PM, Simon Marlow <marlowsd@gmail.com> wrote:
Has the file's modification time changed?  If you're doing this very quickly (within 1 second) then you might run into this:

http://hackage.haskell.org/trac/ghc/ticket/7473

Cheers,
        Simon


On 25/01/13 16:02, JP Moresmau wrote:
When I do that (only adding the target once and just doing load after
the file has changed) the changes in the file are not taken into account
(getNamesInScope for example doesn't give me the name of a type added
inside the file). I probably have my stupid hat on (friday
afternoon...), but when I do remove/load in between it works...

Thanks


On Fri, Jan 25, 2013 at 4:33 PM, Simon Marlow <marlowsd@gmail.com
<mailto:marlowsd@gmail.com>> wrote:

    On 25/01/13 14:30, JP Moresmau wrote:

        Hello, I just want to be sure of what's the fastest way to reload a
        module with the GHC API.
        I have a file whose path is fp
        I load the module with:
        addTarget Target { targetId = TargetFile fp Nothing,
        targetAllowObjCode
        = True, targetContents = Nothing }
        Then I load the module
        load LoadAllTargets
        And when I want to reload the module (the contents of fp have
        changed) I do:
        removeTarget (TargetFile fp Nothing)
        load LoadAllTargets
        and then I rerun my initial code (addTarget, load)


    You should be able to just invoke 'load LoadAllTargets' and omit the
    intermediate remove/load step.  Or is there a reason you want to
    remove the target?

    Cheers,
             Simon




--
JP Moresmau
http://jpmoresmau.blogspot.com/




--
JP Moresmau
http://jpmoresmau.blogspot.com/