Thanks very much for the reply, Joachim.

Oops! I flubbed the example. I really `morph` to distribute over an application of `comp`. New code below (and attached). You're right that I wouldn't want to restrict the type of `morph`, since each `morph` *rule* imposes its own restrictions.

My questions:

*   Is it feasible for GHC to combine the constraints needed LHS and RHS to form an applicability condition?
*   Is there any way I can make the needed constraints explicit in my rewrite rules?
*   Are there any other work-arounds that would enable writing such RHS-constrained rules?

Regards, -- Conal

``` haskell
{-# OPTIONS_GHC -Wall #-}
-- Demonstrate a type checking failure with rewrite rules

module RuleFail where

class C k where comp' :: k b c -> k a b -> k a c

instance C (->) where comp' = (.)

-- Late-inlining version to enable rewriting.
comp :: C k => k b c -> k a b -> k a c
comp = comp'
{-# INLINE [0] comp #-}

morph :: (a -> b) -> k a b
morph = error "morph: undefined"

{-# RULES "morph/(.)" forall f g. morph (g `comp` f) = morph g `comp` morph f #-}

-- • Could not deduce (C k) arising from a use of ‘comp’
--   from the context: C (->)
--     bound by the RULE "morph/(.)"
```


On Mon, Oct 2, 2017 at 3:52 PM, Joachim Breitner <mail@joachim-breitner.de> wrote:
Hi Conal,

The difference is that the LHS of the first rule is mentions the `C k`
constraint (probably unintentionally):

*RuleFail> :t morph comp
morph comp :: C k => k1 (k b c) (k a b -> k a c)

but the LHS of the second rule side does not:

*RuleFail> :t morph addC
morph addC :: Num b => k (b, b) b



A work-around is to add the constraint to `morph`:

    morph :: D k b => (a -> b) -> k a b
    morph = error "morph: undefined"

    but I fear that this work-around is not acceptable to you.

    Joachim

    Am Montag, den 02.10.2017, 14:25 -0700 schrieb Conal Elliott:
    > -- Demonstrate a type checking failure with rewrite rules
>
> module RuleFail where
>
> class C k where comp' :: k b c -> k a b -> k a c
>
> instance C (->) where comp' = (.)
>
> -- Late-inlining version to enable rewriting.
> comp :: C k => k b c -> k a b -> k a c
> comp = comp'
> {-# INLINE [0] comp #-}
>
> morph :: (a -> b) -> k a b
> morph = error "morph: undefined"
>
> {-# RULES "morph/(.)" morph comp = comp #-}  -- Fine



> class D k a where addC' :: k (a,a) a
>
> instance Num a => D (->) a where addC' = uncurry (+)
>
> -- Late-inlining version to enable rewriting.
> addC :: D k a => k (a,a) a
> addC = addC'
> {-# INLINE [0] addC #-}
>
> {-# RULES "morph/addC" morph addC = addC #-}  -- Fail
>
> -- • Could not deduce (D k b) arising from a use of ‘addC’
> --   from the context: D (->) b
>
> -- Why does GHC infer the (C k) constraint for the first rule but not (D k b)
> -- for the second rule?
>
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--
Joachim Breitner
  mail@joachim-breitner.de
  http://www.joachim-breitner.de/