On Tue, Jul 19, 2011 at 02:16, Ting Lei <tinlyx@hotmail.com> wrote:

I have a naive question regarding the basic use of the $ operator, and I am confused why certain times it doesn't seem to work.
e.g.
The following works:

applySkip i f ls = (take i) ls ++ f (drop i ls)

But the following doesn't:

applySkip i f ls = (take i) ls ++ f $ drop i ls

($) has lower precedence than almost every other operator, so your "doesn't work" translates to

> applySkip i f ls = ((take i) ls ++ f) $ (drop i ls)

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brandon s allbery allbery.b@gmail.com
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