Thanks, Brandon,

That's a very clear explanation. I remembered that it's low, but forgot that it's this low.
Maybe it's because of my mis-understanding that in C, infix operators have lower precedence.

Just curious, the following is not allowed in Haskell either for the same reason.

applySkip i f ls = (take i) ls ++ $ f $ drop i ls

I read somewhere that people a couple of hundreds of years ago can manage to express things using ($)-like notation without any parenthesis at all.
Is it possible to define an operator to achieve this which works with infix operators? If so, then ($) and parentheses are then really equivalent.

Best,

Ting