Sebastian Sylvan wrote:
>
> A sorry, I thought the delimiter was a line delimiter. I'm trying to get to
> that fusion goodness by using built-in functions as much as possible...
>
> How about this one:
>
> clean del = B.map ( B.filter (/='\n') ) . B.groupBy (\x y -> (x,y) /=
> (del,'\n'))
>
> That groupBy will group it into groups which don't have the delimiter
> followed by a newline in them (which is the sequence your rows end with),
> then it filters out newlines in each row. You might want to filter out
> spaces first (if there are any) so that you don't get a space between the
> delimiter and newline at the end...
>
>
I think you still need unlines after that so is the time complexity
different to the

unlines . foldr (function including `last') . lines

in my first post? Or is it better for another reason, such as "fusion
goodness"?