So, I'm doing something like this
foldl (>>=) someA list :: Monad m => m a
where
list :: Monad m => [a -> m a],
someA :: Monad m => m a
Is there a more concise way to write this? I don't think foldM is what I
want -- or is it?
--
frigidcode.com
_______________________________________________
Haskell-Cafe mailing list
Haskell-Cafe@haskell.org
http://www.haskell.org/mailman/listinfo/haskell-cafe