On May 19, 2009, at 01:07 , z_axis wrote:
rollDice_t n = do
hd <- openFile "/dev/random" ReadMode
v <- B.hGet hd 1
return (v `mod` n) + 1
No instance for (Integral B.ByteString)
You can't just read a binary string and have it interpreted as a number; you want to use Data.Binary to extract an Int (or whatever) from the ByteString. The same would apply with legacy Strings; in Haskell, String, ByteString, and Int are distinct types and there is no automatic casting. In fact I'm not quite sure why you thought that should work; even Perl would make you unpack(), and C would require you to use an appropriately-aligned buffer and unsafely cast the (char *) to an (int *).