Because each slot stands for a new variable.On Tue, Apr 08, 2014 at 03:58:30AM +0700, Kim-Ee Yeoh wrote:
> On Mon, Apr 7, 2014 at 11:02 PM, ducis <ducis_cn@126.com> wrote:
>
> > It lets your write lambdas with 'slots' without inventing names for the
> > parameters.
> >
> > [s| ı + ı |] = \x y -> x+y
> >
> >
> I have no background in this 'slot lambda' and a search reveals this
> package as the only hit.
>
> Which may explain why I find the example given confusing. Why would [s| 1+1
> |] not be equivalent to \x->x+x ?
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