The last part I cant understand: So I give it for example zipWith ($) (map (\x -> map (const x)) (cycle [True,
False])) [[1,2],[3]]
Okay, because of ($) it takes the first element of the last part which is [1,2] and apply the function on it But how makes this: map (\x -> map (const x)) (cycle [True,
False]) [True,True] from [1,2]? Then he takes [3] but how makes [False] from that?
It easily can be that my functional programming knowledge isn't enough to understand this and maybe I misunderstood it already. But I hope I'll be able to do so..
Thanks: Maur Toter
so
On Sat, Apr 3, 2010 at 4:31 PM, Edward Z. Yang <ezyang@mit.edu> wrote:
Excerpts from Maur Toter's message of Sat Apr 03 10:29:34 -0400 2010: