Hey,

thanks for the help!

Yes it is part of a homework that I can't find out (I am fine with other parts).
This is not the homework itself, just the part of it and I needed help with it, thanks for that!
I would like to understand the solution and not only have it so I would like to ask you:
What does the ($) at zipWith?

Thanks again!


On Sat, Apr 3, 2010 at 6:18 PM, Alexandru Scvortov <scvalex@gmail.com> wrote:
Too many points.

listbool :: [[a]] -> [[Bool]]
listbool = zipWith ($) (map (map . const) (cycle [True, False]))

Cheers,
Alex

On Saturday 03 April 2010 15:13:48 Edward Z. Yang wrote:
> Excerpts from Maur Toter's message of Sat Apr 03 09:54:26 -0400 2010:
> > I am new with Haskell so I think this will be a pretty dumb question.
> > I would like to make a function that makes this:
> >
> > listbool :: [[Int]] -> [[Bool]]
> >
> > in this way:
> > listbool [[1,2],[3,4]] == [[True, True],[False, False]]
> > listbool [[1],[5,5],[5,4],[2]] == [[True],[False, False],[True, True],
> > [False]]
> >
> > So always True from the elements of the first list, False from the
> > elements of the second one, etc...
>
> Sure you can do this.  In fact, the type can be more general:
>
> listbool :: [[a]] -> [[Bool]]
> listbool xs = zipWith ($) (map (\x -> map (const x)) (cycle [True, False]))
> xs
>
> Cheers,
> Edward
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