As Daniel pointed out earlier, this may be of a little bit of help:

http://haskell.org/ghc/docs/latest/html/libraries/base-4.2.0.0/src/Data-List.html#subsequences



On 18 March 2010 04:03, Alexander Solla <ajs@2piix.com> wrote:

On Mar 17, 2010, at 8:33 PM, zaxis wrote:


`allPairs list = [(x,y) | x <- list, y <- list]  ` is not what `combination`
does !
let allPairs list = [(x,y) | x <- list, y <- list]
allPairs [1,2,3]
[(1,1),(1,2),(1,3),(2,1),(2,2),(2,3),(3,1),(3,2),(3,3)]

Yeah, I know that.  I said so specifically.  combination computes the power set of a list.  You said your goal was to compute a set of "two groups".  You don't need the power set in order to compute a set of pairs.  Moreover, computing the power set is a slow operation.  Indeed, it is the source of your slowness.

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Ozgur Akgun