Hi,

I am a newb to Haskell and programming in general, but I was trying to write a basic program to find the elements for the alternating group for any n.

For the symmetric group I wrote something like this

input Data.List

symmetric n = permutations ([1..n])

What if I just want to find the even permutations?  What is the quick and dirty way of doing this?  I was looking at the package Data.Matrix and messing around with permutation matrices, but there has got to be a quicker and easier way of doing it. I am skimming the book learn you a Haskell, but my attention span is pretty short so if someone could direct me in the right direction I'd be much obliged.