On Thu, Jul 3, 2008 at 7:31 PM, Claus Reinke <claus.reinke@talk21.com> wrote:
GHC gives the error:

  Couldn't match expected type `T f1 f1 a'
         against inferred type `T f f a'
  In the expression: blah x
  In the definition of `wrapper': wrapper x = blah x

actually, GHC gives me "could not deduce Blah f a from Blah f1 a"
first. It seems that desugaring type function notation into an additional
constraint helps, so there's something odd going on:

Silly me, I didn't paste the whole type error. Yes, GHC gives both. I should add that I tested this under GHC 6.8.2. But this is known not to work with a (one/two months old) GHC head.

Cheers,

Alexey
 


  class Blah f a where blah :: a -> T f f a
  class A f where type T f :: (* -> *) -> * -> *

  wrapper :: forall a f tf . (Blah f a,T f~tf) => a -> tf f a
  wrapper x = blah x

You're relying on that second f to determine the first, which
then allows T f to determine tf f a. Looks a bit like cyclic
programming at the type level?-) Whereas the desugared
view is that we may not know the type constructor tf yet,
but whatever it is, its first parameter fixes f.

Yet another take on it: tf, the result of T f f a, needs to be
determined by the context, rather than the type function,
and type functions are traditionally bad at reasoning backwards. The extra indirection separates determining
f from applying T f.

I think I'd prefer if that naive desugaring of type function
always worked, without such differences.

Worth a ticket?
Claus