On Mon, May 18, 2009 at 10:02 PM, Ryan Ingram <ryani.spam@gmail.com> wrote:
> Unfortunately, you can't derive Show on Chain as defined, because it
> contains a function:

Sure you can. I just tried the following, and it compiled without complaints.

> import Text.Show.Functions
>
> data Chain = Link Int (Int -> Chain) deriving (Show)

The usual warnings about orphan instances apply, but the purpose of
the Text.Show.Functions module is to provide a standard Show instance
for functions so that libraries (e.g., QuickCheck) don't declare
conflicting instances.

--
Dave Menendez <dave@zednenem.com>
<http://www.eyrie.org/~zednenem/>
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