On Tue, Sep 4, 2012 at 4:21 PM, Alexander Solla <alex.solla@gmail.com> wrote:


On Tue, Sep 4, 2012 at 3:39 AM, Alberto G. Corona <agocorona@gmail.com> wrote:
"Monads are monoids in the category of endofunctors"

This Monoid instance for the endofunctors of the set of all  elements
of (m a)   typematch in Haskell with FlexibleInstances:

instance Monad m => Monoid  (a -> m a) where
   mappend = (>=>)   -- kleisly operator
   mempty  = return

The objects of a Kliesli category for a monad m aren't endofunctors.  You want something like:

instance Monad m => Monoid (m a -> m (m a)) where ...

/These/ are endofunctors, in virtue of join transforming an m (m a) into an (m a).

Actually, even these aren't endofunctors, for a similar reason that :  you "really" want something like

instance Monad m => Monoid (m a -> m a) where
    mempty = id
    mappend = undefined -- exercise left to the reader

(i.e., you want to do plumbing through the Eilenberg-Moore category for a monad, instead of the Kliesli category for a monad -- my last message exposes the kind of plumping you want, but not the right types.)