On 19 May 2017, at 10:10, Jon Purdy <evincarofautumn@gmail.com> wrote:I believe you can use unidirectional pattern synonyms, and only export the patterns, not the constructors.{-# LANGUAGE PatternSynonyms #-}module Tee (T, t1, t2, pattern T1, pattern T2) wheredata T = MkT1 Bool | MkT2 Int | …pattern T1 a <- MkT1 apattern T2 a <- MkT2 a…t1 :: Bool -> Tt2 :: Int -> T…You can pattern-match on T1 just fine, but if you try to use it as a constructor you’ll get “non-bidirectional pattern synonym ‘T1’ used in an expression”.On Fri, May 19, 2017 at 1:43 AM, Andrew Butterfield <Andrew.Butterfield@scss.tcd.ie> wrote:All,
is there any way in Haskell to export a *data* type so that importing modules can pattern match,
but not use the constructors to build anything?
My use case is an AST with invariant - I want the convenience of pattern matching
with the safety of having to build using functions exported by the model rather than the constructors directly.
e.g
given
data T = T1 Bool | T2 Int | TT T T
t1 :: Bool -> T
t2 :: Int -> T
tt :: T -> T -> T
from outside I can write
f(T1 False) = tt (t1 True) (t2 42)
but not
f(T1 False) = TT (T1 True) (T2 42) ?
Regards,
Andrew Butterfield
School of Computer Science & Statistics
Trinity College
Dublin 2, Ireland
_______________________________________________
Haskell-Cafe mailing list
To (un)subscribe, modify options or view archives go to:
http://mail.haskell.org/cgi-bin/mailman/listinfo/haskell- cafe
Only members subscribed via the mailman list are allowed to post.