If you're interested in learning parsec, RWH covered this topic in depth in Chapter 16, Choices and Errors: http://book.realworldhaskell.org/read/using-parsec.html.

On Mon, Jan 2, 2012 at 3:44 AM, max <mk@mtw.ru> wrote:
I want to write a function whose behavior is as follows:

foo "string1\nstring2\r\nstring3\nstring4" = ["string1",
"string2\r\nstring3", "string4"]

Note the sequence "\r\n", which is ignored. How can I do this?

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