On Wednesday 30 April 2014, 13:51:38, Rustom Mody wrote:But what if (⟐) :: b -> b -> a?
> Without claiming to cover all cases, this is a 'principle'
> If we have:
> (⊞) :: a -> a -> b
> (⟐) :: b -> b -> c
> then ⊞'s precedence should be higher than ⟐.