Thanks all,
So, in a do expression
let x = 1 y = 2 etc. in z = 1 + 2
if <bool expr> then etc. else etc.
Is this deviation documented somewhere?
Michael
--- On Thu, 10/8/09, Brandon S. Allbery KF8NH <allbery@ece.cmu.edu> wrote:
From: Brandon S. Allbery KF8NH <allbery@ece.cmu.edu> Subject: Re: [Haskell-cafe] Let it be To: "michael rice" <nowgate@yahoo.com> Cc: "Brandon S. Allbery KF8NH" <allbery@ece.cmu.edu>, haskell-cafe@haskell.org Date: Thursday, October 8, 2009, 11:53 AM
On Oct 8, 2009,
at 11:43 , michael rice wrote: This doesn't:
import System.Random main = do gen <- getStdGen let (randNumber, newGen) = randomR (1,6) gen :: (Int, StdGen) in putStrLn $ "Number is " ++ show randNumber
[michael@localhost ~]$ runhaskell zz.hs
zz.hs:4:2: The last statement in
a 'do' construct must be an expression
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The problem here is that the "do" construct parses things a bit differently; if you're at the same indentation level, it inserts a (>>) on the assumption that the next line is an independent expression, so you need to indent the "in" a bit more to avoid it.
Note however that this usage is common enough that "do" provides a shorthand: you can simply omit the "in", and "let" will be parsed as if it were a statement:
> main = do > gen <- getStdGen > let (randNumber, newGen) = randomR (1,6) gen :: (Int,StdGen) > putStrLn $ "Number is " ++ show randNumber -- electrical and computer engineering, carnegie mellon university KF8NH
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