as provided, this won't compile because v hasn't been defined.

f [] = 0 f (x:xs) = x . f xs

compiles but gives

f :: (Num (a -> c)) => [c -> c] -> a -> c

which seems wrong. maybe I'm not understanding what v is not supposed to be.

I am thinking maybe you want iterate

*Main> take 5 $ iterate (+1) 0
[0,1,2,3,4]

It would be easier to understand your desired function if you would provide an example of desired usage.

t.

PR Stanley <prstanley@ntlworld.com>
Sent by: haskell-cafe-bounces@haskell.org

09/19/2007 02:17 AM

To	haskell-cafe@haskell.org
cc
Subject	[Haskell-cafe] Missing Symbol (2)

Hi Here's another one: f [] = v f (x:xs) = x . f xs The "." is supposed to denote a generic operator - f [] maps to some value v and applied to non-empty list applies head to ? operator. Thanks, Paul _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe

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