Thinking from subway (: foldl ($) LongDef values ?

вторник, 25 декабря 2012 г. пользователь Тимур Амиров писал:
Try folding over data type constructor with $?

вторник, 25 декабря 2012 г. пользователь Magicloud Magiclouds писал:
Forgot to mention, solution without TemplateHaskell.


On Tue, Dec 25, 2012 at 4:59 PM, Magicloud Magiclouds <magicloud.magiclouds@gmail.com> wrote:
Say I have things like:

data LongDec = LongDef a b c ... x y z
values = [ 'a', 'b', 'c', ... 'x', 'y', 'z' ]

Now I want them to be "LongDef 'a' 'b' 'c' ... 'x' 'y' 'z'".
In form, this is something like folding. But since the type changes, so code like following won't work:

foldl (\def value -> def value) LongDef values

Is it possible to do this in some way?
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竹密岂妨流水过
山高哪阻野云飞

And for G+, please use magiclouds#gmail.com.



--
竹密岂妨流水过
山高哪阻野云飞

And for G+, please use magiclouds#gmail.com.


--
Best
Timur DeTeam Amirov
Moscow, Russia



--
Best
Timur DeTeam Amirov
Moscow, Russia