Notably, it is not always useful to suggest removing the `do`,
e.g. I will often write that exact same `do`
block with a let in it in tests, because it is very often the case
that later down the line I do end up wanting to
use binds/stop using binds in the `do` block, and I personally
think the syntactic noise in the git diffs is not worth
the (purely aesthetic?) benefit of not having the `do`.
It's also useful if you're a fan of "abusing"(?)
BlockArguments+`do` to turn
f
(foo bar baz)
(u v)
to
f
do foo bar baz
do u v
To my surprise, hlint (version 3.3.6) did not suggest taking out the do. I ran the following through hlint.
jk :: Booljk = dolet x = Falsenot x
On Wednesday, February 21, 2024 at 04:23:49 AM EST, Noon van der Silk <noonsilk@gmail.com> wrote:
Yeah, it's a bit confusing; I think some tutorials/books do go over the `do` simplification steps. I guess conceptually `do` doesn't mean `Definitely a Monad`, it means `Maybe a Monad` or more `Probably should be a Monad, and if not, just remove the do!`.
On Wed, 21 Feb 2024 at 09:18, Johannes Waldmann <johannes.waldmann@htwk-leipzig.de> wrote:
Dear Cafe,
I was surprised to see ghc accept this code
ghci> do let {x = False}; not x
True
because I initially thought: there's a `do`, so there must be some monad,
but which is it? some implicit Identity monad perhaps?
But the type is indeed plain `Bool`, and the explanation is (I think):
there is a `do` but there is no monad, since the translation according to
( https://www.haskell.org/onlinereport/haskell2010/haskellch3.html#x8-470003.14 )
does never produce `(>>=)`.
So, all is fine, nothing to see here.
Perhaps keep in mind as an edge case, useful to confuse students.
Actually, to motivate them to read the language standard ...
- J.W.
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