On 12/29/06, Neil Mitchell <ndmitchell@gmail.com> wrote:
Hi

>       f1 :: [Int] -> [[Int]]
>        f1 []     = []
>       f1 (a:as) = [a] : f1 as

f1 is simply a map

>       f3 la lb = let a = head la
>                       b = head lb
>                  in if sum a <= sum b then
>                         a : f3 (tail la) lb
>                      else
>                         b : f3 la (tail lb)

Why not use pattern matching to split up la and lb, rather than head/tail?

I would have thought the whole function could be written as a nice
foldr merge, where merge :: [Int] -> [Int] -> [Int]. Thats only a
guess at the top of my head though, not worked out properly.

Is this homework? If so its useful to state when you post the question :)


Hi Neil,

I am not sure how to express f1 with map?  how do I say
(lambda (ls)
    (map (lambda (x) (list x))
    ls))
in Haskell?  map ([])  ?

Here is my new f3:
f3 :: [[Int]] -> [[Int]] -> [[Int]]
f3 [] lb = lb
f3 la [] = la
f3 la@(a:as) lb@(b:bs) = if sum a <= sum b then
                             a : f3 as lb
                         else
                             b : f3 la bs

(btw, yes this is homework assigned by prof. Quan in quantum computing class :))
Thanks,
Quan