yep ... that is exactly what I meant!! so can I use more $'s or must I use parens (as you did) to disambiguate?

Vasili

On Mon, Jan 5, 2009 at 12:18 PM, Ross Mellgren <rmm-haskell@z.odi.ac> wrote:
Did you mean:

B.intercalate (B.intercalate ByteString [ByteString]) [ByteString]

($) applies all the way to the right, so you were giving the inner intercalate two lists of ByteString.

-Ross


On Jan 5, 2009, at 1:17 PM, Galchin, Vasili wrote:

Hi Max,

       That is what should happen .... The inner B.intercalate will produce the ByteString to be used by the B.intercalate.  ??

Vasili

On Mon, Jan 5, 2009 at 12:13 PM, Max Rabkin <max.rabkin@gmail.com> wrote:
2009/1/5 Galchin, Vasili <vigalchin@gmail.com>:
> Hello,
>
>       I have the following:
>
>             B.intercalate $ B.intercalate
>                   ByteString
>                   [ByteString]
>                   [ByteString]
>
>       I get a type error with this. If I  comment out the 2nd B.intercalate
> and the third parameter I get no type errors.

B.intercalate needs a ByteString and a list of ByteStrings. Two
B.intercalates need two ByteStrings and two lists of ByteStrings.

--Max

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