On Tue, May 5, 2009 at 8:49 PM, Nico Rolle <nrolle@web.de> wrote:

Hi everyone.

I have a problem.
A function is recieving a lambda expression like this:
(\ x y -> x > y)
or like this
(\ x y z a -> (x > y) && (z < a)

my problem is now i know i have a list filled with the parameters for
the lambda expression.
but how can i call that expression?
[parameters] is my list of parameters for the lambda expression.
lambda_ex is my lambda expression

is there a function wich can do smth like that?

lambda _ex (unfold_parameters parameters)

Why not:

lam1 = \[x, y] -> x > y
lam2 = \[x, y, z, a] -> (x > y) && (z < a)

doLam :: Ord a => ([a] -> Bool) -> [a] -> Bool
doLam lam params = lam params

So, this will work fine:

doLam lam1 [1, 2]
doLam lam2 [1,2,3,4]