> On Aug 10, 2017, at 5:08 PM, Wolfgang Jeltsch
> <wolfgang-it@jeltsch.info> wrote:
>
> Is there also a solution that does not involve using this
> (unimplemented) feature?
I get the feeling there is a better way to do this, but I found
something of a hack that I think does what you want. Using
Data.Type.Equality, you can match on Refl to bring the `b` into scope.
import Data.Type.Equality
f :: forall a. IsListType a -> ()
f IsListType = case Refl of
(Refl :: (a :~: [b])) -> ()
This is sort of silly, though.
Alexis
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