Dear Cafe,
The expression
\x -> f x == g x
is a testable property, as long as values for x can be randomly
generated. For clarity I'd prefer a point-free style, e.g.
f ≡ g
Are there extensions to QuickCheck that let me write this? The
QuickCheck package itself does not seem to contain such an operator. My
current work-around is a
newtype ExtensionalEquality a b
that holds two functions of type (a -> b) and a Testable instance for
it. But I've got a hunch that I re-invented some wheel here. (My
ExtensionalEquality is isomorphic to
Refl (a -> b) (a -> b)
but Refl ist conceptually about type equality, not term equality.)
Thanks
Olaf
_______________________________________________
Haskell-Cafe mailing list
To (un)subscribe, modify options or view archives go to:
http://mail.haskell.org/cgi-bin/mailman/listinfo/haskell-cafe
Only members subscribed via the mailman list are allowed to post.