On Wed, Jun 16, 2010 at 6:55 AM, Tillmann Rendel <rendel@mathematik.uni-marburg.de> wrote:
Bas van Dijk wrote:
data Iso (⇝) a b = Iso { ab ∷ a ⇝ b
                      , ba ∷ b ⇝ a
                      }

type IsoFunc = Iso (→)

instance Category (⇝) ⇒ Category (Iso (⇝)) where
  id = Iso id id
  Iso bc cb . Iso ab ba = Iso (bc . ab) (ba . cb)

An 'Iso (⇝)' also _almost_ forms an Arrow (if (⇝) forms an Arrow):

instance Arrow (⇝) ⇒ Arrow (Iso (⇝)) where
   arr f = Iso (arr f) undefined

   first  (Iso ab ba) = Iso (first  ab) (first  ba)
   second (Iso ab ba) = Iso (second ab) (second ba)
   Iso ab ba *** Iso cd dc = Iso (ab *** cd) (ba *** dc)
   Iso ab ba &&& Iso ac ca = Iso (ab &&& ac) (ba . arr fst)
                                      -- or: (ca . arr snd)

But note the unfortunate 'undefined' in the definition of 'arr'.

This comes up every couple of years, I think the first attempt at formulating Iso wrongly as an arrow was in the "There and Back Again" paper.

http://citeseerx.ist.psu.edu/viewdoc/summary?doi=10.1.1.60.7278

It comes up now and again, because the types seem to _almost_ fit. =) The reason is that an arrow is a closed pre-Cartesian category with a little bit of extra structure. Isomorphisms and embedding-projection pairs are a bit too constrained to meet even the requirements of a  pre-Cartesian category, however.

This seems to suggest that all the methods besides 'arr' need to move
to a separate type class.

You may be interesting in following the construction of a more formal set of categories that build up the functionality of arrow incrementally in category-extras. An arrow can be viewed as a closed pre-cartesian category with an embedding of Hask. Iso on the other hand is much weaker. The category is isomorphisms, or slightly weaker, the category of embedding-projection pairs doesn't have all the properties you might expect at first glance.

You an define it as a Symmetric Monoidal category over (,) using a Bifunctor for (,) over Iso:

http://hackage.haskell.org/packages/archive/category-extras/0.53.5/doc/html/Control-Functor.html

the assocative laws from:

http://hackage.haskell.org/packages/archive/category-extras/0.52.1/doc/html/Control-Category-Associative.html

The definitions of Braided and Symmetric from:

http://hackage.haskell.org/packages/archive/category-extras/0.52.1/doc/html/Control-Category-Braided.html

and the Monoidal class from:

http://hackage.haskell.org/packages/archive/category-extras/0.52.1/doc/html/Control-Category-Monoidal.html

This gives you a weak product-like construction. But as you noted, fst and snd cannot be defined, so you cannot define Cartesian

http://hackage.haskell.org/packages/archive/category-extras/0.53.5/doc/html/Control-Category-Cartesian.html

let alone a CCC

http://hackage.haskell.org/packages/archive/category-extras/0.53.5/doc/html/Control-Category-Cartesian-Closed.html

or Arrow. =(

 

Wouldn't it be better to have a definition like this:

 class Category (~>) => Products (~>) where
   (***) :: (a ~> b) -> (c ~> d) -> ((a, c) ~> (b, d))
   (&&&) :: (a ~> b) -> (a ~> c) -> (a ~> (b, c))
   fst :: (a, b) ~> a
   snd :: (a, b) ~> b

You've stumbled across the concept of a Cartesian category (or at least, technically 'pre-Cartesian', though the type of product also needs to be a parameter or the dual of a category with sums won't be a category with products.

http://hackage.haskell.org/packages/archive/category-extras/0.52.1/doc/html/Control-Category-Cartesian.html

Or even like this:

 class Category (~>) => Products (~>) where
   type Product a b
   (***) :: (a ~> b) -> (c ~> d) -> (Product a c ~> Product b d)
   (&&&) :: (a ~> b) -> (a ~> c) -> (a ~> Product b c)
   fst :: Product a b ~> a
   snd :: Product a b ~> b

This was the formulation I had originally used in category-extras for categories. I swapped to MPTCs due to implementation defects in type families at the time, and intend to swap back at some point in the future.
 
Unfortunately, I don't see how to define fst and snd for the Iso example, so I wonder whether Iso has products?

It does not. =)

-Edward Kmett