a = [1,1,1,1]
b = [0,1,2,3]
d = [0,0,0,0]
for i in b:
for j in c:
if (i+j)<3:
d[i+j] += a[i]
My just work implementation in Haskell
Another people implementation in Haskell with Monad and it turns out complex and very imperatively.
Do you have any cool solution in FP way?
Thanks.
-Simon