yep

add  Show to your abstrac container. , for example:

data SDynamic=  forall a.Show a => SDynamic a

instance Show SDynamic where
     show (SDynamic a)= show a

2009/10/16 David Virebayre <dav.vire+haskell@gmail.com>

On Fri, Oct 16, 2009 at 8:19 PM, Andrew Coppin
<andrewcoppin@btinternet.com> wrote:
> Is there any way that you can turn an arbitrary Haskell value into a string?

> I rephrase: There *is* a way to turn arbitrary values into strings. I know
> there is, because the GHCi debugger *does* it. The question is, does anybody
> know of an /easy/ way to do this?

Ghci only displays values with a Show instance.
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