(f*(f+2*g), f^2 + g^2)
as opposed to the return value of
(f^2+g^2, g*(2*f-g))
What is it about the boolean value that requires two entirely seperate things to be done?
On Friday, May 6, 2016 at 6:46:26 PM UTC-5, Michael Litchard wrote:He suggested breaking up a guard into two diffeent functions, which I can do, but I don't know what to call them because I don't know why the operations are different. I'm referring to this section:I've been working on a project that needs a good fibonacci generator, and I'm to the point where can now improve upon this one:thanks to this guy:
https://wiki.haskell.org/The_Fibonacci_sequence#Fastest_Fib_in_the_West
https://groups.google.com/forum/#!topic/haskell-cafe/HUgbAUCvCp4fib' (f, g) p | p = (f*(f+2*g), f^2 + g^2) | otherwise = (f^2+g^2, g*(2*f-g))
I'd like to know the reason why each guard does two entirely different things, so I know what to call the functions when I seperate them out.Clearly `p` is a Bool, and it comes from the expression:map (toEnum . fromIntegral) $ unfoldl divs nWhat's going on in `toEnum . fromIntegral` is that a remainder (either 0 or 1 - it blows up for anything else) is being converted to a Bool, with 0 mapping to False and 1 mapping to True. So `isOdd` would be a more descriptive name for `p`.