On Sat, Dec 10, 2011 at 12:33, Henning Thielemann wrote:
I have (x :: Set key) and (m :: Map key a) and want to remove all keys and corresponding values from m that are in x. I could solve it efficiently with a

differenceSet :: Map key a -> Set key -> Map key a

I have implemented this in the past, though it was certainly inefficient. It would be nice to have something similar and efficient.

Regards,
Sean