- Beginners - Haskell.org

Thanks
by CEO'Riley 19 Dec '11

19 Dec '11

Michael, Benjamin, thanks much. Regards, CEO'Riley Charles E. O'Riley Jr.

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Re: [Haskell-beginners] Installing packages ?
by Michael Xavier 19 Dec '11

19 Dec '11

I would begin by looking at the docs for that package: http://hackage.haskell.org/package/StatisticalMethods-0.0.0.1 In particular, the Modules section. Find the functions you want from the modules that contain them and import them into your program. IE if you wanted to work with a confusion matrix, whatever that is, and your program looks like: module MyModule where ..... You instead do: module MyModule where import Statistics.ConfusionMatrix ... do stuff with the functions in that module ... You may also find this handy: http://haskell.org/haskellwiki/Import_modules_properly and this tutorial: http://learnyouahaskell.com/modules Hope that helps On Sun, Dec 18, 2011 at 9:39 PM, CEO'Riley <ceoriley(a)gmail.com> wrote: > The package was StatisticalMethods. Unfortunately, I’m new at this and > very anal. When you say import it into the project I’m using, I assume you > mean via the Haskell program (WinGHC). If that’s correct, then what nexts? > **** > > ** ** > > ** ** > > ** ** > > Regards,**** > > CEO’Riley**** > > Charles E. O’Riley Jr.**** > > ** ** > > *From:* Michael Xavier [mailto:nemesisdesign@gmail.com] > *Sent:* Sunday, December 18, 2011 11:37 PM > *To:* ceoriley(a)gmail.com > *Cc:* beginners(a)haskell.org > *Subject:* Re: [Haskell-beginners] Installing packages ?**** > > ** ** > > Import it into a project you're using.**** > > ** ** > > What package was it?**** > > On Sun, Dec 18, 2011 at 9:19 PM, CEO'Riley <ceoriley(a)gmail.com> wrote:**** > > **** > > Hello all,**** > > **** > > I recently installed a statistical package using cabal on my Windows > machine. I need to know what to do next in order to get access to the > statistical functionality. I’ve looked but have not been able to fine the > answer. Thanks.**** > > **** > > **** > > **** > > Regards,**** > > CEO’Riley**** > > Charles E. O’Riley Jr.**** > > **** > > > _______________________________________________ > Beginners mailing list > Beginners(a)haskell.org > http://www.haskell.org/mailman/listinfo/beginners**** > > > > **** > > ** ** > > -- > Michael Xavier > http://www.michaelxavier.net**** > > LinkedIn <http://www.linkedin.com/pub/michael-xavier/13/b02/a26>**** > > ** ** > -- Michael Xavier http://www.michaelxavier.net LinkedIn <http://www.linkedin.com/pub/michael-xavier/13/b02/a26>

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Installing packages ?
by CEO'Riley 19 Dec '11

19 Dec '11

Hello all, I recently installed a statistical package using cabal on my Windows machine. I need to know what to do next in order to get access to the statistical functionality. I've looked but have not been able to fine the answer. Thanks. Regards, CEO'Riley Charles E. O'Riley Jr.

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How to remove some duplication from this code?
by Peter Hall 15 Dec '11

15 Dec '11

I'm following this article about GADTs [http://en.wikibooks.org/wiki/Haskell/GADT] and it suggests, as an exercise, to handle invalid trees at runtime, without GADTs, when evaluating a simple arithmetic syntax tree. My attempt is below. It seems to work, but I could do with some feedback, as it isn't quite satisfactory. It feels like I should be able to remove some of the duplicated code in the eval function, and also in evalIntExpr and evalBoolExpr, which are identical except for having Left and Right reversed. Thanks, Peter -------- Arithmetic.hs module Arithmetic where import Data.Maybe data Expr = I Int | B Bool | Add Expr Expr | Mult Expr Expr | Eq Expr Expr eval :: Expr -> Maybe (Either Bool Int) eval (B b) = return $ Left b eval (I i) = return $ Right i eval (Mult e1 e2) = do a1 <- evalIntExpr e1 a2 <- evalIntExpr e2 return $ Right $ a1 * a2 eval (Add e1 e2) = do a1 <- evalIntExpr e1 a2 <- evalIntExpr e2 return $ Right $ a1 + a2 eval (Eq e1 e2) = do a1 <- evalIntExpr e1 a2 <- evalIntExpr e2 return $ Left $ a1 == a2 evalIntExpr :: Expr -> Maybe Int evalIntExpr e = eval e >>= unwrap where unwrap (Right x) = Just x unwrap (Left x) = Nothing evalBoolExpr :: Expr -> Maybe Bool evalBoolExpr e = eval e >>= unwrap where unwrap (Left x) = Just x unwrap (Right x) = Nothing ------- Main.hs module Main ( main ) where import Arithmetic import Data.Maybe import Data.Either test :: Expr test = Eq (Mult (Add (I 1) (I 2) ) (I 5) ) (I 15) main :: IO () main = do putStrLn $ case eval test of Nothing -> "Invalid expression" Just (Left x) -> show x Just (Right x) -> show x

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Read package name, version from .cabal file
by Shakthi Kannan 14 Dec '11

14 Dec '11

Hi, I am trying to read a .cabal find and print the package name and version. Here is the code snippet: === Code === getName :: FilePath -> IO () getName cabal = do gdesc <- readPackageDescription normal cabal let desc = flattenPackageDescription gdesc final = pkgName $ package desc putStrLn final === END === === Output === Couldn't match expected type `[Char]' with actual type `PackageName' === END === I see that the method 'package' from: http://www.haskell.org/cabal/release/cabal-latest/doc/API/Cabal/Distributio… allows me to return the PackageIdentifier. Using pkgName returns a PackageName. http://www.haskell.org/cabal/release/cabal-latest/doc/API/Cabal/Distributio… But, how can I obtain the string value from it? Appreciate any help in this regard. Thanks! SK -- Shakthi Kannan http://www.shakthimaan.com

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What's the difference between those two solution?
by Haisheng Wu 13 Dec '11

13 Dec '11

Hello, I'm trying to solve Euler problem 104 with the solution "My Solution" below but it takes quite long time therefore I quite. Then I turn to haskell wiki for better solution which work well but I can not figure out why it is better than mine. I'm wondering whether more function call decrease the performance. Could you please help a little? Thank you. *-- | My Solution * main = print $ snd $ head $ dropWhile (\(x,y) -> (not . bothNinePandigit "123456789") x) (zip fibs [1..]) bothNinePandigit digits n = isFirstNinePandigit digits n && isLastNinePandigit digits n isLastNinePandigit digits n = digits == sort (lastDigits 9 n) isFirstNinePandigit digits n = digits == sort (firstDigits 9 n) firstDigits k n = take k (show n) lastDigits k n = show (n `mod` 10^k) fibs = 0 : 1 : zipWith (+) fibs (tail fibs) *-- | From Haskell Wiki * fibs = 1 : 1 : zipWith (+) fibs (tail fibs) isFibPan n = let a = n `mod` 1000000000 b = sort (show a) c = sort $ take 9 $ show n in b == "123456789" && c == "123456789" ex_104 = snd $ head $ dropWhile (\(x,y) -> (not . isFibPan) x) (zip fibs [1..])

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Pattern matching over functions
by Giacomo Tesio 13 Dec '11

13 Dec '11

Hi Haskellers, I'm wondering why, given that functions and referential transparency are first class citizens in haskell, it isn't possible to write a mapping function this way: f1 :: a -> b f2 :: a -> b f3 :: c -> a -> b map :: (a -> b) -> T a -> T b map f1 = anEquivalentOfF1InTCategory map f2 = anEquivalentOfF2InTCategory map f3 $ c = anEquivalentOfF3withCInTCategory map unknown = aGenericMapInTCategory Is it "just" the implementation complexity of the feature in ghc that prevents this? Or is it "conceptually" wrong? At a first look, I thought that most of complexity here should be related to function's equality, but than I thought that the function full name should uniquely map from the category of meanings in the programmer mind to the category of implementations available to the compiler's. Giacomo

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In Search Of a clue... (Defining and making use of a type)
by Allen S. Rout 13 Dec '11

13 Dec '11

So, I'm approaching a problem which I think I understand pretty well. I'm a novice to Haskell, though, and I'm having difficulty even getting started with e.g. data types and building more complex structures. Here's what I'm trying to do; this is an xmonad customization/extension. My end goal is thus: Innermost: a 'Screen Tuple' , which I'm calling a 'ScrUple'. This represents a statement like 'screen 0 is displaying workspace "mail"'. Next: A variable-length list of these, I'm calling 'ScrConfig'. It means something like 'display this workspace on screen 0, that one on 1, etc'. Next: [ haven't gotten here ] a hash, or something: pairs of 'label : ScrConfig'. I don't know if the most haskelly way to do that is to build another type, and then another aggregate of that type.. In PERL, it'd be something vaguely like: $configs = { 'initial' => { \(0,"mail"), \(1,"web"), \(2,"jabber") } 'project' => { \(4,"editor"), \(1,"compile"), \(2,"jabber") } }; Here's what I'm doing so far, ---------------- data ScrUple = ScrUple { xineramascreen :: Integer , workspace :: String } deriving (Show) data ScrConfig = ScrConfig [ ScrUple ] deriving (Show) s1 = ScrUple 0 "mail" s2 = ScrUple 1 "web" ScrConfig sc1 =ScrConfig( [s2 s1] ) ; main = putStrLn $ show sc1[1] ------------------ and I get errors like: play.hs:17:27: Couldn't match expected type `ScrUple -> ScrUple' against inferred type `ScrUple' In the expression: s2 s1 In the first argument of `ScrConfig', namely `([s2 s1])' In the expression: ScrConfig ([s2 s1]) play.hs:21:19: Couldn't match expected type `[t] -> String' against inferred type `String' In the second argument of `($)', namely `show sc1 [1]' In the expression: putStrLn $ show sc1 [1] In the definition of `main': main = putStrLn $ show sc1 [1] ------------------- ... I feel like I'm thinking about the problem wrong, because this kind of "Here's how you build up a data structure" doesn't seem to be in the tutorials. I've been working through LYAH and Gentle Introduction, but so far haven't found things that feel related. I'd be delighted with pointers to the right parts of the Fine Manual, and similarly pleased with discursion on how to think about this data storage problem from a haskelly point of view. - Allen S. Rout

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Re: [Haskell-beginners] Fwd: Averaging a string of numbers
by Ben Kolera 12 Dec '11

12 Dec '11

There is some magic here that I'm not quite groking. Sorry for my slowness; but I seem to be missing a step: This is how I'd expect liftA2 to work ( and is why I didn't use lift in my initial response ): *Main Control.Applicative Data.Monoid> liftA2 max Nothing (Just 1) Nothing I expected all the magic to be the applicative class instance that was generated for Maximum by the GeneralizedNewtypeDeriving extension, but why do these not work? *Main Control.Applicative Data.Monoid> liftA2 max (Maximum Nothing) (Maximum (Just 1)) Maximum {getMaximum = Nothing} *Main Control.Applicative Data.Monoid> mempty `mappend` (Maximum (Just 1)) `mappend` (Maximum (Just 2) ) Maximum {getMaximum = Nothing} When this obviously works just fine? *Main Control.Applicative Data.Monoid> main Stats {ct = Sum {getSum = 0}, sm = Sum {getSum = 0.0}, mn = Minimum {getMinimum = Nothing}, mx = Maximum {getMaximum = Nothing}} Stats {ct = Sum {getSum = 1}, sm = Sum {getSum = 1.0}, mn = Minimum {getMinimum = Just 1.0}, mx = Maximum {getMaximum = Just 1.0}} Stats {ct = Sum {getSum = 1}, sm = Sum {getSum = 2.0}, mn = Minimum {getMinimum = Just 2.0}, mx = Maximum {getMaximum = Just 2.0}} Stats {ct = Sum {getSum = 2}, sm = Sum {getSum = 3.0}, mn = Minimum {getMinimum = Just 1.0}, mx = Maximum {getMaximum = Just 2.0}} Sorry if I am missing something obvious and this question is really silly! On Mon, Dec 12, 2011 at 5:18 PM, Dean Herington & Elizabeth Lacey <heringtonlacey(a)mindspring.com> wrote: > At 8:21 AM +1000 12/12/11, Ben Kolera wrote: >> >> That is just because you are calling min and max against the Maybe >> rather than on the values inside of your maybes. Max is working >> because there is an instance of Ord for Maybe and >> >> Nothing > Just n > Just ( n + 1 ) > > > You have the right idea, but replace `>` above by `<`. > > >> >> This is certainly not the most elegant solution ( I am a beginner, too >> ) but here is what I would do: >> >> instance Monoid Stats where >> mempty = Stats 0 Nothing Nothing 0 >> mappend (Stats sm1 mn1 mx1 len1) (Stats sm2 mn2 mx2 len2) = >> Stats >> (sm1 + sm2) >> (chooseMaybe min mn1 mn2) >> (chooseMaybe max mx1 mx2) >> (len1 + len2) >> >> chooseMaybe _ Nothing Nothing = Nothing >> chooseMaybe _ (Just a) Nothing = Just a >> chooseMaybe _ Nothing (Just b) = Just b >> chooseMaybe f (Just a) (Just b) = Just $ f a b >> >> >> Hopefully this quick answer can get you on your way to solving your >> problem and we can both learn a better way of doing it when someone >> optimises my solution. ;) > > > You've got the principle just right. Here's a way to cast it that makes it > apparent that `Stats` is a monoid in a "componentwise" fashion. > > > {-# LANGUAGE GeneralizedNewtypeDeriving #-} > > import Data.Monoid > import Control.Applicative > > > -- | Monoid under minimum. > newtype Minimum a = Minimum { getMinimum :: Maybe a } > deriving (Eq, Ord, Functor, Applicative, Read, Show) > > instance Ord a => Monoid (Minimum a) where > mempty = Minimum Nothing > mappend = liftA2 min > > -- | Monoid under maximum. > newtype Maximum a = Maximum { getMaximum :: Maybe a } > deriving (Eq, Ord, Functor, Applicative, Read, Show) > > instance Ord a => Monoid (Maximum a) where > mempty = Maximum Nothing > mappend = liftA2 max > > data Stats = Stats { > ct :: Sum Int, > sm :: Sum Double, > mn :: Minimum Double, > mx :: Maximum Double } > deriving (Eq, Show, Read) > > instance Monoid Stats where > mempty = Stats mempty mempty mempty mempty > mappend (Stats ct1 sm1 mn1 mx1) (Stats ct2 sm2 mn2 mx2) = > Stats (ct1 `mappend` ct2) > (sm1 `mappend` sm2) > (mn1 `mappend` mn2) > (mx1 `mappend` mx2) > > > mkStats v = Stats (Sum 1) (Sum v) (Minimum (Just v)) (Maximum (Just v)) > > st0, st1, st2, st3 :: Stats > > st0 = mempty > st1 = mkStats 1 > st2 = mkStats 2 > st3 = st1 `mappend` st2 > > main = mapM_ print [st0, st1, st2, st3]

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IO ( stuff )
by Paul Monday 12 Dec '11

12 Dec '11

I've hammered through the bulk of my issues as I try to build a matrix that consists of random numbers, but the final hurdle is mixing pure and impure functions. Does "impurity" from something like a random number generator or file I/O have to move it's way all the way through my code? Here is the specific example. I have a function that makes a row in a matrix, it looks like this: makerow :: Int -> (Float, Float) -> IO (U.Vector Float) The IO (U.Vector Float) is the result of the random number generation that is an impure call, making this an impure result. I want to compose this into a list makerows :: Int -> Int -> (Float, Float) -> [U.Vector Float] makerows 0 _ _ = [] makerows r n range = makerow n range : makerows r' n range where r' = r - 1 But, of course, I can't mix the IO (U.Vector Float) with a U.Vector Float The compilation result in: Couldn't match expected type `U.Vector Float' with actual type `IO (U.Vector Float)' In the return type of a call of `makerow' So, at some point, I have to lift I believe … is there a simple lifting solution? It initially seemed that Monads were the solution … but liftIO resulted in the same thing … just with Monad (U.Vector Float) … There is just some "simple" Haskellism I'm missing here, but after an ginormous amount of reading and googling, it is still eluding me :( Any thoughts (besides the one page I found that helpfully … basically … said "Go back to Java" ;-) Paul Monday Parallel Scientific, LLC. paul.monday(a)parsci.com

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