No need to apologize for grammar. =) There are lots of people in the Haskell community with many different levels of English fluency, we all just try to communicate as best we can. As for your question, I am not quite sure I understand what you want. Do you mean that you want to "zip" the lists together, applying each function to one element? As in specificFilter [(>3), even, (<19)] [6, 7, 8] = [6,8] because 6>3 and 8>19 (but 7 is not even)? If that is what you mean, then you could do something like specificFilter ps xs = map snd . filter fst $ zipWith (\p x -> (p x, x)) ps xs If you mean something else, then maybe you could give some examples of what you want? -Brent On Sun, Jul 07, 2013 at 02:32:21PM -0300, Igor Pinheiro Leão wrote:
Hum.. really sorry about the grammar mistakes.
2013/7/7 Igor Pinheiro Leão
Hi Guys, sorry in upsetting you again. Is there a way in which I can filter one list of function, one function at time, to a list of elements, declaring this and only this function.
It would be exactly like this:
specifcFilter :: [(a->Bool)] -> [a] -> [a]
where for each element of type 'a' on the second list it would exist a function on the first list that would be applied to it filtering.
Kind regards, Igor
-- Igor Vinícius Graduando em Ciência da Computação
-- Igor Vinícius Graduando em Ciência da Computação
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